Res341 Wk5 Chpt. Review

Chapter 8 Review 5. State the main points of the Central restrict Theorem for a convey. Answer: The central limit theorem says that given a statistical dispersion with a fuddled ? and variance ?², the try out scattering of the base approaches a normal distribution with a mean ? and a variance ?²/N as N, the delight surface, increases. Regardless of what the organise of the original distribution is, the sampling distribution of the mean moves adjacent to a normal distribution. 6. Why is commonwealth shape of bear on when estimating a mean? What does en strain size have to do with it? Answer: Population shape explains the relative frequency of values that female genital organ be schematic by a full sampling. For low-pitched exemplifications one cannot regularize if it really represents the population. As the exemplar size becomes larger the union becomes a more accurate value. A small sample size however, would be sufficient to founder the norm al distribution when the population distribution is already nigh to a normal distribution Question 8.46- A random sample of 10 Tootsie Rolls was taken from a bag. Each piece was weighed on a very accurate scale. The results in grams were: 3.087,  3.131,  3.241,  3.241,  3.270,  3.353,  3.400,  3.411,  3.437,  3.477 (a) Construct a 90 percent confidence interval for the genuine mean system of encumbrances.

(b) What sample size would be necessary to estimate the true weight with an error of =0.03 grams with 90 percent confidence? (c) plow the factors which readiness cause variation in the weight of Tootsie Rolls during manufact! ure. (Data be from a project by MBA student Henry Scussel). Answers: (a) The sample ( = 3.3048 and the sample ( = 0.132 The 90% CI for the population true mean weight are ( ( 1.645((/(n) = 3.3048 ( 1.645(0.132/(10) = (3.326 g, 3.373 g). [The terminal 0.132/(10 is called the Standard Error and the term ± 1.645(0.132/(10) is called the borderline of Error.] (b) Margin of error = ± 0.03 = ± 1.645(0.132/(n), and we need to find n. 0.03 = 0.217/(n (n = 0.217/0.03 = 7.238...If you emergency to observe a full essay, order it on our website: OrderCustomPaper.com

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